(8/x)-1=8/(x-1)

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Solution for (8/x)-1=8/(x-1) equation: 


D( x )

x = 0

x-1 = 0

x = 0

x = 0

x-1 = 0

x-1 = 0

x-1 = 0 // + 1

x = 1

x in (-oo:0) U (0:1) U (1:+oo)

8/x-1 = 8/(x-1) // - 8/(x-1)

8/x-(8/(x-1))-1 = 0

8/x-8*(x-1)^-1-1 = 0

8/x-8/(x-1)-1 = 0

(-8*x)/(x*(x-1))+(8*(x-1))/(x*(x-1))+(-1*x*(x-1))/(x*(x-1)) = 0

8*(x-1)-1*x*(x-1)-8*x = 0

x-x^2-8 = 0

x-x^2-8 = 0

x-x^2-8 = 0

DELTA = 1^2-(-8*(-1)*4)

DELTA = -31

DELTA < 0

1 = 0

1/(x*(x-1)) = 0

1/(x*(x-1)) = 0 // * x*(x-1)

1 = 0

x belongs to the empty set

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