(8/x+2)+(7/1-x)+1=0

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Solution for (8/x+2)+(7/1-x)+1=0 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

8/x-x+7/1+1+2 = 0

8/x-x+1+2+7 = 0

8*x^-1-1*x^1+10*x^0 = 0

(10*x^1-1*x^2+8*x^0)/(x^1) = 0 // * x^2

x^1*(10*x^1-1*x^2+8*x^0) = 0

x^1

10*x-x^2+8 = 0

10*x-x^2+8 = 0

DELTA = 10^2-(-1*4*8)

DELTA = 132

DELTA > 0

x = (132^(1/2)-10)/(-1*2) or x = (-132^(1/2)-10)/(-1*2)

x = (2*33^(1/2)-10)/(-2) or x = (-2*33^(1/2)-10)/(-2)

x in { (2*33^(1/2)-10)/(-2), (-2*33^(1/2)-10)/(-2)} 

x in { (2*33^(1/2)-10)/(-2), (-2*33^(1/2)-10)/(-2) }

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