(8/x-3)+(8/x)=10

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Solution for (8/x-3)+(8/x)=10 equation: 



(8/x-3)+(8/x)=10

We move all terms to the left:

(8/x-3)+(8/x)-(10)=0



Domain of the equation: x-3)!=0

x∈R





Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(8/x-3)+(+8/x)-10=0

We get rid of parentheses

8/x+8/x-3-10=0

We multiply all the terms by the denominator


-3*x-10*x+8+8=0

We add all the numbers together, and all the variables

-13x+16=0

We move all terms containing x to the left, all other terms to the right

-13x=-16

x=-16/-13

x=1+3/13

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