(8/y)+(4/y)=3

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Solution for (8/y)+(4/y)=3 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

8/y+4/y = 3 // - 3

8/y+4/y-3 = 0

12*y^-1 = 3 // : 12

y^-1 = 1/4

-1 < 0

1/(y^1) = 1/4 // * y^1

1 = 1/4*y^1 // : 1/4

4 = y^1

y = 4

y = 4

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