(80-2x)=(92-3x)

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Solution for (80-2x)=(92-3x) equation: 



(80-2x)=(92-3x)

We move all terms to the left:

(80-2x)-((92-3x))=0

We add all the numbers together, and all the variables

(-2x+80)-((-3x+92))=0

We get rid of parentheses

-2x-((-3x+92))+80=0



We calculate terms in parentheses: -((-3x+92)), so:

(-3x+92)

We get rid of parentheses

-3x+92

Back to the equation:

-(-3x+92)



We get rid of parentheses

-2x+3x-92+80=0

We add all the numbers together, and all the variables

x-12=0

We move all terms containing x to the left, all other terms to the right

x=12

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