(81x+3)(x-7)=9x(9x-6)

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Solution for (81x+3)(x-7)=9x(9x-6) equation: 



(81x+3)(x-7)=9x(9x-6)

We move all terms to the left:

(81x+3)(x-7)-(9x(9x-6))=0

We multiply parentheses ..

(+81x^2-567x+3x-21)-(9x(9x-6))=0



We calculate terms in parentheses: -(9x(9x-6)), so:

9x(9x-6)

We multiply parentheses

81x^2-54x

Back to the equation:

-(81x^2-54x)



We get rid of parentheses

81x^2-81x^2-567x+3x+54x-21=0

We add all the numbers together, and all the variables

-510x-21=0

We move all terms containing x to the left, all other terms to the right

-510x=21

x=21/-510

x=-7/170

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