(81x+3)(x-7)=9x(9x-6)

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Solution for (81x+3)(x-7)=9x(9x-6) equation:



(81x+3)(x-7)=9x(9x-6)
We move all terms to the left:
(81x+3)(x-7)-(9x(9x-6))=0
We multiply parentheses ..
(+81x^2-567x+3x-21)-(9x(9x-6))=0
We calculate terms in parentheses: -(9x(9x-6)), so:
9x(9x-6)
We multiply parentheses
81x^2-54x
Back to the equation:
-(81x^2-54x)
We get rid of parentheses
81x^2-81x^2-567x+3x+54x-21=0
We add all the numbers together, and all the variables
-510x-21=0
We move all terms containing x to the left, all other terms to the right
-510x=21
x=21/-510
x=-7/170

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