(82-10x)/(40-x)=24

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Solution for (82-10x)/(40-x)=24 equation: 



(82-10x)/(40-x)=24

We move all terms to the left:

(82-10x)/(40-x)-(24)=0



Domain of the equation: (40-x)!=0

We move all terms containing x to the left, all other terms to the right

-x!=-40

x!=-40/-1

x!=+40

x∈R



We add all the numbers together, and all the variables

(-10x+82)/(-1x+40)-24=0

We multiply all the terms by the denominator


(-10x+82)-24*(-1x+40)=0

We multiply parentheses

(-10x+82)+24x-960=0

We get rid of parentheses

-10x+24x+82-960=0

We add all the numbers together, and all the variables

14x-878=0

We move all terms containing x to the left, all other terms to the right

14x=878

x=878/14

x=62+5/7

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