(820-10x)/(40-x)=24

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Solution for (820-10x)/(40-x)=24 equation:



(820-10x)/(40-x)=24
We move all terms to the left:
(820-10x)/(40-x)-(24)=0
Domain of the equation: (40-x)!=0
We move all terms containing x to the left, all other terms to the right
-x!=-40
x!=-40/-1
x!=+40
x∈R
We add all the numbers together, and all the variables
(-10x+820)/(-1x+40)-24=0
We multiply all the terms by the denominator
(-10x+820)-24*(-1x+40)=0
We multiply parentheses
(-10x+820)+24x-960=0
We get rid of parentheses
-10x+24x+820-960=0
We add all the numbers together, and all the variables
14x-140=0
We move all terms containing x to the left, all other terms to the right
14x=140
x=140/14
x=10

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