(8Y)/(2y+4)+(6y-6)/(3y+6)=(3y-8)/(y-2)

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Solution for (8Y)/(2y+4)+(6y-6)/(3y+6)=(3y-8)/(y-2) equation: 


D( x )

y-2 = 0

3*y+6 = 0

2*y+4 = 0

y-2 = 0

y-2 = 0

y-2 = 0

x naleu017Cy do R

3*y+6 = 0

3*y+6 = 0

3*y+6 = 0

x naleu017Cy do R

2*y+4 = 0

2*y+4 = 0

2*y+4 = 0

x naleu017Cy do R

x belongs to the empty set

(8*Y)/(2*y+4)+(6*y-6)/(3*y+6) = (3*y-8)/(y-2)

x belongs to the empty set

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