(8a+-12a)-3+2=(7a-12a)-3+8-a

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Solution for (8a+-12a)-3+2=(7a-12a)-3+8-a equation: 



(8a+-12a)-3+2=(7a-12a)-3+8-a

We move all terms to the left:

(8a+-12a)-3+2-((7a-12a)-3+8-a)=0

We add all the numbers together, and all the variables

(-4a)-((-5a)-3+8-a)-3+2=0

We add all the numbers together, and all the variables

(-4a)-((-5a)-3+8-a)-1=0

We get rid of parentheses

-4a-((-5a)-3+8-a)-1=0



We calculate terms in parentheses: -((-5a)-3+8-a), so:

(-5a)-3+8-a

determiningTheFunctionDomain
(-5a)-a-3+8

We add all the numbers together, and all the variables

-1a+(-5a)+5

We get rid of parentheses

-1a-5a+5

We add all the numbers together, and all the variables

-6a+5

Back to the equation:

-(-6a+5)



We get rid of parentheses

-4a+6a-5-1=0

We add all the numbers together, and all the variables

2a-6=0

We move all terms containing a to the left, all other terms to the right

2a=6

a=6/2

a=3

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