(8b-63)+(3b-10)=180

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Solution for (8b-63)+(3b-10)=180 equation: 



(8b-63)+(3b-10)=180

We move all terms to the left:

(8b-63)+(3b-10)-(180)=0

We get rid of parentheses

8b+3b-63-10-180=0

We add all the numbers together, and all the variables

11b-253=0

We move all terms containing b to the left, all other terms to the right

11b=253

b=253/11

b=23

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