(8c-5)+(6c+3)=90

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Solution for (8c-5)+(6c+3)=90 equation: 



(8c-5)+(6c+3)=90

We move all terms to the left:

(8c-5)+(6c+3)-(90)=0

We get rid of parentheses

8c+6c-5+3-90=0

We add all the numbers together, and all the variables

14c-92=0

We move all terms containing c to the left, all other terms to the right

14c=92

c=92/14

c=6+4/7

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