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(8d+4)(6d+8)=180
We move all terms to the left:
(8d+4)(6d+8)-(180)=0
We multiply parentheses ..
(+48d^2+64d+24d+32)-180=0
We get rid of parentheses
48d^2+64d+24d+32-180=0
We add all the numbers together, and all the variables
48d^2+88d-148=0
a = 48; b = 88; c = -148;
Δ = b2-4ac
Δ = 882-4·48·(-148)
Δ = 36160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{36160}=\sqrt{64*565}=\sqrt{64}*\sqrt{565}=8\sqrt{565}$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(88)-8\sqrt{565}}{2*48}=\frac{-88-8\sqrt{565}}{96} $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(88)+8\sqrt{565}}{2*48}=\frac{-88+8\sqrt{565}}{96} $
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