(8m+1)(m+6)=0

Solution for (8m+1)(m+6)=0 equation:

(8m+1)(m+6)=0

We multiply parentheses ..

(+8m^2+48m+m+6)=0

We get rid of parentheses

8m^2+48m+m+6=0

We add all the numbers together, and all the variables

8m^2+49m+6=0

a = 8; b = 49; c = +6;
Δ = b2-4ac
Δ = 492-4·8·6
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2209}=47$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-47}{2*8}=\frac{-96}{16}
=-6
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+47}{2*8}=\frac{-2}{16}
=-1/8
$