(8m-2)m=2

Solution for (8m-2)m=2 equation:

(8m-2)m=2

We move all terms to the left:

(8m-2)m-(2)=0

We multiply parentheses

8m^2-2m-2=0

a = 8; b = -2; c = -2;
Δ = b2-4ac
Δ = -22-4·8·(-2)
Δ = 68
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{68}=\sqrt{4*17}=\sqrt{4}*\sqrt{17}=2\sqrt{17}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{17}}{2*8}=\frac{2-2\sqrt{17}}{16}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{17}}{2*8}=\frac{2+2\sqrt{17}}{16}
$