(8r-3)+(7r+1)=-6

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Solution for (8r-3)+(7r+1)=-6 equation: 



(8r-3)+(7r+1)=-6

We move all terms to the left:

(8r-3)+(7r+1)-(-6)=0

We add all the numbers together, and all the variables

(8r-3)+(7r+1)+6=0

We get rid of parentheses

8r+7r-3+1+6=0

We add all the numbers together, and all the variables

15r+4=0

We move all terms containing r to the left, all other terms to the right

15r=-4

r=-4/15

r=-4/15

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