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(8t+12)/(2t+3)=4
We move all terms to the left:
(8t+12)/(2t+3)-(4)=0
Domain of the equation: (2t+3)!=0We multiply all the terms by the denominator
We move all terms containing t to the left, all other terms to the right
2t!=-3
t!=-3/2
t!=-1+1/2
t∈R
(8t+12)-4*(2t+3)=0
We multiply parentheses
(8t+12)-8t-12=0
We get rid of parentheses
8t-8t+12-12=0
We add all the numbers together, and all the variables
=0
t=0/1
t=0
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