If it's not what You are looking for type in the equation solver your own equation and let us solve it.
D( x )
6-(2*i) = 0
6-(2*i) = 0
6-(2*i) = 0
6-2*i = 0
6-2*i = 0
x naleu017Cy do R
x belongs to the empty set
(3*i+8*t)/(6-(2*i)) = 0
x belongs to the empty set
| -5sqrt(27)= | | (a^3b/a^-4b^3)^3 | | r^3-7r^2+14r-8=0 | | 6+4(2)-3+9= | | -5x+7=2 | | 0.4x+12.1=x-1.64 | | 0.1x+17.7=x-2.37 | | (3s-5)/(4S*2-4S+1) | | 16=-2t+38 | | x^5+x^2+X= | | -5+-10+-5+-4= | | c=-15-7 | | 3y+6=42 | | 3*x= | | 4(6z-1)-5(z+1)=14(z+1) | | 8(p-0.25)=4(2p-0.5) | | 2x*-5= | | 2x-8y=-5 | | (4x^2y+2-xy)-(6xy^2-5xy)= | | -3n(4n+3)=6 | | -7(3+t)=4(t+6) | | -6+15+(-9)= | | -5x+7=2-7 | | 10x^2+39x+14= | | x=y^3-15 | | 5x^2+20x-100=0 | | 2-(w+2)(w+2)=8 | | 4f(f+3)+5=17+4f | | 7(13)+7(-13)=n | | 16(12*12)=n | | 7-2x-x=-2 | | 7x^2+62x+15=0 |