(8v-3)(v+8)=0

Solution for (8v-3)(v+8)=0 equation:

(8v-3)(v+8)=0

We multiply parentheses ..

(+8v^2+64v-3v-24)=0

We get rid of parentheses

8v^2+64v-3v-24=0

We add all the numbers together, and all the variables

8v^2+61v-24=0

a = 8; b = 61; c = -24;
Δ = b2-4ac
Δ = 612-4·8·(-24)
Δ = 4489
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4489}=67$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(61)-67}{2*8}=\frac{-128}{16}
=-8
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(61)+67}{2*8}=\frac{6}{16}
=3/8
$