(8v-5)+(6-7v)-1=7-(v-1)+(4v+4)

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Solution for (8v-5)+(6-7v)-1=7-(v-1)+(4v+4) equation: 



(8v-5)+(6-7v)-1=7-(v-1)+(4v+4)

We move all terms to the left:

(8v-5)+(6-7v)-1-(7-(v-1)+(4v+4))=0

We add all the numbers together, and all the variables

(8v-5)+(-7v+6)-(7-(v-1)+(4v+4))-1=0

We get rid of parentheses

8v-7v-(7-(v-1)+(4v+4))-5+6-1=0



We calculate terms in parentheses: -(7-(v-1)+(4v+4)), so:

7-(v-1)+(4v+4)

determiningTheFunctionDomain
-(v-1)+(4v+4)+7

We get rid of parentheses

-v+4v+1+4+7

We add all the numbers together, and all the variables

3v+12

Back to the equation:

-(3v+12)



We add all the numbers together, and all the variables

v-(3v+12)=0

We get rid of parentheses

v-3v-12=0

We add all the numbers together, and all the variables

-2v-12=0

We move all terms containing v to the left, all other terms to the right

-2v=12

v=12/-2

v=-6

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