(8v-7)(v-1)=0

Solution for (8v-7)(v-1)=0 equation:

(8v-7)(v-1)=0

We multiply parentheses ..

(+8v^2-8v-7v+7)=0

We get rid of parentheses

8v^2-8v-7v+7=0

We add all the numbers together, and all the variables

8v^2-15v+7=0

a = 8; b = -15; c = +7;
Δ = b2-4ac
Δ = -152-4·8·7
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-1}{2*8}=\frac{14}{16}
=7/8
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+1}{2*8}=\frac{16}{16}
=1
$