(8w+5)(5w+7)=(10w-7)(4w-3)

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Solution for (8w+5)(5w+7)=(10w-7)(4w-3) equation: 



(8w+5)(5w+7)=(10w-7)(4w-3)

We move all terms to the left:

(8w+5)(5w+7)-((10w-7)(4w-3))=0

We multiply parentheses ..

(+40w^2+56w+25w+35)-((10w-7)(4w-3))=0



We calculate terms in parentheses: -((10w-7)(4w-3)), so:

(10w-7)(4w-3)

We multiply parentheses ..

(+40w^2-30w-28w+21)

We get rid of parentheses

40w^2-30w-28w+21

We add all the numbers together, and all the variables

40w^2-58w+21

Back to the equation:

-(40w^2-58w+21)



We get rid of parentheses

40w^2-40w^2+56w+25w+58w+35-21=0

We add all the numbers together, and all the variables

139w+14=0

We move all terms containing w to the left, all other terms to the right

139w=-14

w=-14/139

w=-14/139

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