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(8x)-(x+3)=(x+3)
We move all terms to the left:
(8x)-(x+3)-((x+3))=0
We get rid of parentheses
8x-x-((x+3))-3=0
We calculate terms in parentheses: -((x+3)), so:We add all the numbers together, and all the variables
(x+3)
We get rid of parentheses
x+3
Back to the equation:
-(x+3)
7x-(x+3)-3=0
We get rid of parentheses
7x-x-3-3=0
We add all the numbers together, and all the variables
6x-6=0
We move all terms containing x to the left, all other terms to the right
6x=6
x=6/6
x=1
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