(8x)=(2x+80)

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Solution for (8x)=(2x+80) equation: 



(8x)=(2x+80)

We move all terms to the left:

(8x)-((2x+80))=0



We calculate terms in parentheses: -((2x+80)), so:

(2x+80)

We get rid of parentheses

2x+80

Back to the equation:

-(2x+80)



We get rid of parentheses

8x-2x-80=0

We add all the numbers together, and all the variables

6x-80=0

We move all terms containing x to the left, all other terms to the right

6x=80

x=80/6

x=13+1/3

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