(8x+-3)=(7x+1)

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Solution for (8x+-3)=(7x+1) equation: 



(8x+-3)=(7x+1)

We move all terms to the left:

(8x+-3)-((7x+1))=0

We add all the numbers together, and all the variables

(8x-3)-((7x+1))=0

We get rid of parentheses

8x-((7x+1))-3=0



We calculate terms in parentheses: -((7x+1)), so:

(7x+1)

We get rid of parentheses

7x+1

Back to the equation:

-(7x+1)



We get rid of parentheses

8x-7x-1-3=0

We add all the numbers together, and all the variables

x-4=0

We move all terms containing x to the left, all other terms to the right

x=4

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