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(8x+1)(7x+4)=0
We multiply parentheses ..
(+56x^2+32x+7x+4)=0
We get rid of parentheses
56x^2+32x+7x+4=0
We add all the numbers together, and all the variables
56x^2+39x+4=0
a = 56; b = 39; c = +4;
Δ = b2-4ac
Δ = 392-4·56·4
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(39)-25}{2*56}=\frac{-64}{112} =-4/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(39)+25}{2*56}=\frac{-14}{112} =-1/8 $
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