(8x+1)(8x+1+1)=0

Solution for (8x+1)(8x+1+1)=0 equation:

(8x+1)(8x+1+1)=0

We add all the numbers together, and all the variables

(8x+1)(8x+2)=0

We multiply parentheses ..

(+64x^2+16x+8x+2)=0

We get rid of parentheses

64x^2+16x+8x+2=0

We add all the numbers together, and all the variables

64x^2+24x+2=0

a = 64; b = 24; c = +2;
Δ = b2-4ac
Δ = 242-4·64·2
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-8}{2*64}=\frac{-32}{128}
=-1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+8}{2*64}=\frac{-16}{128}
=-1/8
$