(8x+1)-(4x-5)=2

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Solution for (8x+1)-(4x-5)=2 equation:


Simplifying
(8x + 1) + -1(4x + -5) = 2

Reorder the terms:
(1 + 8x) + -1(4x + -5) = 2

Remove parenthesis around (1 + 8x)
1 + 8x + -1(4x + -5) = 2

Reorder the terms:
1 + 8x + -1(-5 + 4x) = 2
1 + 8x + (-5 * -1 + 4x * -1) = 2
1 + 8x + (5 + -4x) = 2

Reorder the terms:
1 + 5 + 8x + -4x = 2

Combine like terms: 1 + 5 = 6
6 + 8x + -4x = 2

Combine like terms: 8x + -4x = 4x
6 + 4x = 2

Solving
6 + 4x = 2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + 4x = 2 + -6

Combine like terms: 6 + -6 = 0
0 + 4x = 2 + -6
4x = 2 + -6

Combine like terms: 2 + -6 = -4
4x = -4

Divide each side by '4'.
x = -1

Simplifying
x = -1

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