(8x+1)/2=(t+8)/4+(t-6)/4

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Solution for (8x+1)/2=(t+8)/4+(t-6)/4 equation: 


x in (-oo:+oo)

(8*x+1)/2 = (t+8)/4+(t-6)/4 // - (t+8)/4+(t-6)/4

(8*x+1)/2-((t+8)/4)-((t-6)/4) = 0

(8*x+1)/2+(-1*(t+8))/4+(-1*(t-6))/4 = 0

(4*(8*x+1))/(2*4)+(-1*2*(t+8))/(2*4)+(-1*2*(t-6))/(2*4) = 0

4*(8*x+1)-1*2*(t+8)-1*2*(t-6) = 0

32*x-2*t-2*t-12+12 = 0

32*x-4*t = 0

(32*x-4*t)/(2*4) = 0

(32*x-4*t)/(2*4) = 0 // * 2*4

32*x-4*t = 0

32*x-4*t = 0 // + -4*t

32*x = -(-4*t) // : 32

x = (-(-4*t))/32

x = t/8

x = t/8

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