(8x+1)3x+2=2

Solution for (8x+1)3x+2=2 equation:

(8x+1)3x+2=2

We move all terms to the left:

(8x+1)3x+2-(2)=0

We add all the numbers together, and all the variables

(8x+1)3x=0

We multiply parentheses

24x^2+3x=0

a = 24; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·24·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*24}=\frac{-6}{48}
=-1/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*24}=\frac{0}{48}
=0
$