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(8x+10)=(3x+60)
We move all terms to the left:
(8x+10)-((3x+60))=0
We get rid of parentheses
8x-((3x+60))+10=0
We calculate terms in parentheses: -((3x+60)), so:We get rid of parentheses
(3x+60)
We get rid of parentheses
3x+60
Back to the equation:
-(3x+60)
8x-3x-60+10=0
We add all the numbers together, and all the variables
5x-50=0
We move all terms containing x to the left, all other terms to the right
5x=50
x=50/5
x=10
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