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(8x+11)(12x-1)=70
We move all terms to the left:
(8x+11)(12x-1)-(70)=0
We multiply parentheses ..
(+96x^2-8x+132x-11)-70=0
We get rid of parentheses
96x^2-8x+132x-11-70=0
We add all the numbers together, and all the variables
96x^2+124x-81=0
a = 96; b = 124; c = -81;
Δ = b2-4ac
Δ = 1242-4·96·(-81)
Δ = 46480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{46480}=\sqrt{16*2905}=\sqrt{16}*\sqrt{2905}=4\sqrt{2905}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(124)-4\sqrt{2905}}{2*96}=\frac{-124-4\sqrt{2905}}{192} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(124)+4\sqrt{2905}}{2*96}=\frac{-124+4\sqrt{2905}}{192} $
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