(8x+2)(14x-7)=0

Solution for (8x+2)(14x-7)=0 equation:

(8x+2)(14x-7)=0

We multiply parentheses ..

(+112x^2-56x+28x-14)=0

We get rid of parentheses

112x^2-56x+28x-14=0

We add all the numbers together, and all the variables

112x^2-28x-14=0

a = 112; b = -28; c = -14;
Δ = b2-4ac
Δ = -282-4·112·(-14)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7056}=84$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-84}{2*112}=\frac{-56}{224}
=-1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+84}{2*112}=\frac{112}{224}
=1/2
$