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(8x+2)(18x-20)=7x
We move all terms to the left:
(8x+2)(18x-20)-(7x)=0
We add all the numbers together, and all the variables
-7x+(8x+2)(18x-20)=0
We multiply parentheses ..
(+144x^2-160x+36x-40)-7x=0
We get rid of parentheses
144x^2-160x+36x-7x-40=0
We add all the numbers together, and all the variables
144x^2-131x-40=0
a = 144; b = -131; c = -40;
Δ = b2-4ac
Δ = -1312-4·144·(-40)
Δ = 40201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-131)-\sqrt{40201}}{2*144}=\frac{131-\sqrt{40201}}{288} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-131)+\sqrt{40201}}{2*144}=\frac{131+\sqrt{40201}}{288} $
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