(8x+2)+(6x-1)-108=0

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Solution for (8x+2)+(6x-1)-108=0 equation: 



(8x+2)+(6x-1)-108=0

We get rid of parentheses

8x+6x+2-1-108=0

We add all the numbers together, and all the variables

14x-107=0

We move all terms containing x to the left, all other terms to the right

14x=107

x=107/14

x=7+9/14

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