(8x+3)+6=4(x-3)

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Solution for (8x+3)+6=4(x-3) equation:



(8x+3)+6=4(x-3)
We move all terms to the left:
(8x+3)+6-(4(x-3))=0
We get rid of parentheses
8x-(4(x-3))+3+6=0
We calculate terms in parentheses: -(4(x-3)), so:
4(x-3)
We multiply parentheses
4x-12
Back to the equation:
-(4x-12)
We add all the numbers together, and all the variables
8x-(4x-12)+9=0
We get rid of parentheses
8x-4x+12+9=0
We add all the numbers together, and all the variables
4x+21=0
We move all terms containing x to the left, all other terms to the right
4x=-21
x=-21/4
x=-5+1/4

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