(8x+3)-8=9(x-5)

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Solution for (8x+3)-8=9(x-5) equation:



(8x+3)-8=9(x-5)
We move all terms to the left:
(8x+3)-8-(9(x-5))=0
We get rid of parentheses
8x-(9(x-5))+3-8=0
We calculate terms in parentheses: -(9(x-5)), so:
9(x-5)
We multiply parentheses
9x-45
Back to the equation:
-(9x-45)
We add all the numbers together, and all the variables
8x-(9x-45)-5=0
We get rid of parentheses
8x-9x+45-5=0
We add all the numbers together, and all the variables
-1x+40=0
We move all terms containing x to the left, all other terms to the right
-x=-40
x=-40/-1
x=+40

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