(8x+3)=(4x-2)

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Solution for (8x+3)=(4x-2) equation: 



(8x+3)=(4x-2)

We move all terms to the left:

(8x+3)-((4x-2))=0

We get rid of parentheses

8x-((4x-2))+3=0



We calculate terms in parentheses: -((4x-2)), so:

(4x-2)

We get rid of parentheses

4x-2

Back to the equation:

-(4x-2)



We get rid of parentheses

8x-4x+2+3=0

We add all the numbers together, and all the variables

4x+5=0

We move all terms containing x to the left, all other terms to the right

4x=-5

x=-5/4

x=-1+1/4

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