(8x+4)+(11x-2)=(17x+10)

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Solution for (8x+4)+(11x-2)=(17x+10) equation: 



(8x+4)+(11x-2)=(17x+10)

We move all terms to the left:

(8x+4)+(11x-2)-((17x+10))=0

We get rid of parentheses

8x+11x-((17x+10))+4-2=0



We calculate terms in parentheses: -((17x+10)), so:

(17x+10)

We get rid of parentheses

17x+10

Back to the equation:

-(17x+10)



We add all the numbers together, and all the variables

19x-(17x+10)+2=0

We get rid of parentheses

19x-17x-10+2=0

We add all the numbers together, and all the variables

2x-8=0

We move all terms containing x to the left, all other terms to the right

2x=8

x=8/2

x=4

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