(8x+4)=(11x-41)

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Solution for (8x+4)=(11x-41) equation: 



(8x+4)=(11x-41)

We move all terms to the left:

(8x+4)-((11x-41))=0

We get rid of parentheses

8x-((11x-41))+4=0



We calculate terms in parentheses: -((11x-41)), so:

(11x-41)

We get rid of parentheses

11x-41

Back to the equation:

-(11x-41)



We get rid of parentheses

8x-11x+41+4=0

We add all the numbers together, and all the variables

-3x+45=0

We move all terms containing x to the left, all other terms to the right

-3x=-45

x=-45/-3

x=+15

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