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(8x+5)=2(x-20)
We move all terms to the left:
(8x+5)-(2(x-20))=0
We get rid of parentheses
8x-(2(x-20))+5=0
We calculate terms in parentheses: -(2(x-20)), so:We get rid of parentheses
2(x-20)
We multiply parentheses
2x-40
Back to the equation:
-(2x-40)
8x-2x+40+5=0
We add all the numbers together, and all the variables
6x+45=0
We move all terms containing x to the left, all other terms to the right
6x=-45
x=-45/6
x=-7+1/2
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