(8x+6)-2(6x-12)/3-2(4x+4)=36

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Solution for (8x+6)-2(6x-12)/3-2(4x+4)=36 equation:



(8x+6)-2(6x-12)/3-2(4x+4)=36
We move all terms to the left:
(8x+6)-2(6x-12)/3-2(4x+4)-(36)=0
We multiply parentheses
(8x+6)-2(6x-12)/3-8x-8-36=0
We get rid of parentheses
8x-2(6x-12)/3-8x+6-8-36=0
We multiply all the terms by the denominator
8x*3-2(6x-12)-8x*3+6*3-8*3-36*3=0
We add all the numbers together, and all the variables
8x*3-2(6x-12)-8x*3-114=0
We multiply parentheses
8x*3-12x-8x*3+24-114=0
Wy multiply elements
24x-12x-24x+24-114=0
We add all the numbers together, and all the variables
-12x-90=0
We move all terms containing x to the left, all other terms to the right
-12x=90
x=90/-12
x=-7+1/2

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