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(8x+78)-2=(2x+114)-2
We move all terms to the left:
(8x+78)-2-((2x+114)-2)=0
We get rid of parentheses
8x-((2x+114)-2)+78-2=0
We calculate terms in parentheses: -((2x+114)-2), so:We add all the numbers together, and all the variables
(2x+114)-2
We get rid of parentheses
2x+114-2
We add all the numbers together, and all the variables
2x+112
Back to the equation:
-(2x+112)
8x-(2x+112)+76=0
We get rid of parentheses
8x-2x-112+76=0
We add all the numbers together, and all the variables
6x-36=0
We move all terms containing x to the left, all other terms to the right
6x=36
x=36/6
x=6
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