(8x+8)(9x+1)=180

Solution for (8x+8)(9x+1)=180 equation:

(8x+8)(9x+1)=180

We move all terms to the left:

(8x+8)(9x+1)-(180)=0

We multiply parentheses ..

(+72x^2+8x+72x+8)-180=0

We get rid of parentheses

72x^2+8x+72x+8-180=0

We add all the numbers together, and all the variables

72x^2+80x-172=0

a = 72; b = 80; c = -172;
Δ = b2-4ac
Δ = 802-4·72·(-172)
Δ = 55936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{55936}=\sqrt{64*874}=\sqrt{64}*\sqrt{874}=8\sqrt{874}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-8\sqrt{874}}{2*72}=\frac{-80-8\sqrt{874}}{144}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+8\sqrt{874}}{2*72}=\frac{-80+8\sqrt{874}}{144}
$