(8x-1)(2x+8)=0

Solution for (8x-1)(2x+8)=0 equation:

(8x-1)(2x+8)=0

We multiply parentheses ..

(+16x^2+64x-2x-8)=0

We get rid of parentheses

16x^2+64x-2x-8=0

We add all the numbers together, and all the variables

16x^2+62x-8=0

a = 16; b = 62; c = -8;
Δ = b2-4ac
Δ = 622-4·16·(-8)
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4356}=66$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(62)-66}{2*16}=\frac{-128}{32}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(62)+66}{2*16}=\frac{4}{32}
=1/8
$