(8x-1)+(8x-1)=(6x+12)

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Solution for (8x-1)+(8x-1)=(6x+12) equation: 



(8x-1)+(8x-1)=(6x+12)

We move all terms to the left:

(8x-1)+(8x-1)-((6x+12))=0

We get rid of parentheses

8x+8x-((6x+12))-1-1=0



We calculate terms in parentheses: -((6x+12)), so:

(6x+12)

We get rid of parentheses

6x+12

Back to the equation:

-(6x+12)



We add all the numbers together, and all the variables

16x-(6x+12)-2=0

We get rid of parentheses

16x-6x-12-2=0

We add all the numbers together, and all the variables

10x-14=0

We move all terms containing x to the left, all other terms to the right

10x=14

x=14/10

x=1+2/5

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