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(8x-10)(7x+1)=171
We move all terms to the left:
(8x-10)(7x+1)-(171)=0
We multiply parentheses ..
(+56x^2+8x-70x-10)-171=0
We get rid of parentheses
56x^2+8x-70x-10-171=0
We add all the numbers together, and all the variables
56x^2-62x-181=0
a = 56; b = -62; c = -181;
Δ = b2-4ac
Δ = -622-4·56·(-181)
Δ = 44388
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{44388}=\sqrt{324*137}=\sqrt{324}*\sqrt{137}=18\sqrt{137}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-62)-18\sqrt{137}}{2*56}=\frac{62-18\sqrt{137}}{112} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-62)+18\sqrt{137}}{2*56}=\frac{62+18\sqrt{137}}{112} $
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