(8x-12)/12=(3x-1)/4

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Solution for (8x-12)/12=(3x-1)/4 equation: 



(8x-12)/12=(3x-1)/4

We move all terms to the left:

(8x-12)/12-((3x-1)/4)=0

We calculate fractions


8x/()+(-((3x-1)*12)/()=0



We calculate terms in parentheses: +(-((3x-1)*12)/(), so:

-((3x-1)*12)/(

We multiply all the terms by the denominator


-((3x-1)*12)



We calculate terms in parentheses: -((3x-1)*12), so:

(3x-1)*12

We multiply parentheses

36x-12

Back to the equation:

-(36x-12)



We get rid of parentheses

-36x+12

Back to the equation:

+(-36x+12)



We get rid of parentheses

8x/()-36x+12=0

We multiply all the terms by the denominator


8x-36x*()+12*()=0

We add all the numbers together, and all the variables

8x-36x*()=0

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