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(8x-12)=(2x+33)
We move all terms to the left:
(8x-12)-((2x+33))=0
We get rid of parentheses
8x-((2x+33))-12=0
We calculate terms in parentheses: -((2x+33)), so:We get rid of parentheses
(2x+33)
We get rid of parentheses
2x+33
Back to the equation:
-(2x+33)
8x-2x-33-12=0
We add all the numbers together, and all the variables
6x-45=0
We move all terms containing x to the left, all other terms to the right
6x=45
x=45/6
x=7+1/2
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