(8x-12)=(3x+28)=90

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Solution for (8x-12)=(3x+28)=90 equation: 



(8x-12)=(3x+28)=90

We move all terms to the left:

(8x-12)-((3x+28))=0

We get rid of parentheses

8x-((3x+28))-12=0



We calculate terms in parentheses: -((3x+28)), so:

(3x+28)

We get rid of parentheses

3x+28

Back to the equation:

-(3x+28)



We get rid of parentheses

8x-3x-28-12=0

We add all the numbers together, and all the variables

5x-40=0

We move all terms containing x to the left, all other terms to the right

5x=40

x=40/5

x=8

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